Code Breaker: Challenge #1 _

Difficulty Level: 2 Padlocks

Your score: 0 pts

Check the following pseudo-code to work out the passcode needed to complete this level:
BEGIN
digit1 = (2 + (6/3)) * 2
digit2 = 3^2
digit3 = 10 DIV 3
digit4 = 10 MOD 3
passcode = ""
passcode = passcode + digit1 + digit2
passcode = passcode + digit3 + digit4
OUTPUT passcode
END
Hint: DIV means "quotient",
e.g. 7 DIV 3 = 2 (as 7 = 2 x 3 + 1)
e.g. 10 DIV 2 = 5 (as 10 = 5 x 2 + 0)

MOD means "remainder",
e.g. 7 MOD 3 = 1 (as 7 = 2 x 3 + 1)
e.g. 10 MOD 2 = 0 (as 10 = 5 x 2 + 0)

^ means "to the power of",
e.g. 5^2 = 52 = 25
Enter your passcode:
ERROR
SUCCESS
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